1.23
2.0
main
test-branch
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| 1 | #include <assert.h>
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| 2 | #pragma PARSE_ACSL
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| 3 | $input int N;
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| 4 | $assume(N > 0);
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| 5 | int a[N];
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| 6 |
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| 7 | int main() {
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| 8 | int i, j;
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| 9 | int minIdx = 0;
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| 10 |
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| 11 | $havoc(&a);
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| 12 | /* Following loop invariants is incorrect, one either needs to
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| 13 | specify minIdx in loop invariants or put the minIdx inside the
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| 14 | loop. The previous prototype relies upon the correct
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| 15 | specification of loop assigns, it cannot detect this. */
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| 16 |
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| 17 | /*@ loop invariant 0 <= i && i <= N;
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| 18 | @ loop invariant \forall int t; N-i+1<=t && t <N ==>
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| 19 | @ a[t] <= a[t-1];
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| 20 | @ loop invariant \forall int t; 0 <= t && t < N-i && i > 0 ==>
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| 21 | @ a[t] >= a[N-i];
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| 22 | @ loop assigns i, j, a[0 .. N-1];
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| 23 | @*/
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| 24 | for (i = 0; i < N; i++) {
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| 25 | /*@ loop invariant 0<=j && j <=N-i && 0<=minIdx &&
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| 26 | @ minIdx<N-i;
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| 27 | @ loop invariant \forall int t; 0<=t && t <j ==>
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| 28 | @ a[t] >= a[minIdx];
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| 29 | @ loop assigns j, minIdx;
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| 30 | @*/
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| 31 | for (j = 0; j < N-i; j++)
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| 32 | if (a[j] < a[minIdx])
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| 33 | minIdx = j;
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| 34 |
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| 35 | int tmp = a[minIdx];
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| 36 |
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| 37 | a[minIdx] = a[N-i-1];
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| 38 | a[N-i-1] = tmp;
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| 39 | minIdx = 0;
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| 40 | }
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| 41 | assert($forall (int i : 1 .. N-1) a[i] <= a[i-1]);
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| 42 | return 0;
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| 43 | }
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