source: CIVL/examples/arithmetic/ex3_simple.cvl

#include <math.h>
#include <stdio.h>

#define L 5
$input double a, b;
$assume(a > 0);
$assume(a == b);

void main() {
  double y = a;
  int i;
  
  for(i=0; i<L; i++) {
    y = sqrt(y);
    printf("the %d time y = %f\n", i, y);
  }
  for(int i=0; i<L; i++) {
    y = y * y;
    printf("the %d time y = %f\n", i, y);
  }
    
  $assert(y == b);
}